Solving the Physics Problem: Position of Object Leaving Compressed Spring

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The discussion focuses on determining the position at which an object leaves a compressed spring on an inclined air track at a 30-degree angle. It highlights the dynamics of the object as it accelerates after the spring is released, emphasizing the transition from potential energy to kinetic energy. The key point is that the object will continue to move forward until its velocity surpasses that of the spring as it begins to regain potential energy. The problem requires calculating the exact moment and position of separation based on the spring constant, mass of the object, and the incline. The analysis suggests that understanding the forces and energy transformations involved is crucial for solving the problem.
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An object is place against a compressed spring at the bottom of an air track that slope upward at an angle 30. When the spring is release, find at which position, the object leave the spring?
Given: the spring is compressed A, the spring constant is k, m is mass of object, mass of spring is negligible
 
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What have you done so far?
 
The problem is that, after the object releases from the spring, it will accelerate.. if the velocity of object is greater than spring, the object will leave. but when?
 
Initially the ball accelerates with the spring as it loses its potential energy , till the point , the spring passes its mean position and starts gaining the potential energy, but the ball remains in motion it had gained . Work on it.

BJ
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
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