Solving the Puzzle: Ball Thrown Upward

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A ball thrown upward at an initial speed of 40 m/s reaches a maximum height determined by the kinematic equations of motion. The time it spends in the air is calculated as 8 seconds, based on the initial speed and acceleration due to gravity. To find the maximum height, the appropriate displacement formula should be used, taking into account initial velocity, final velocity, and acceleration. The discussion emphasizes the need to clarify known variables and apply the correct equations. Understanding these concepts is crucial for solving the problem accurately.
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Homework Statement



A ball is thrown straight up with an initial speed of 40 m/s. (Neglect air resistance.)
How high does it go? how long does it stay i the air



Homework Equations



i know the second part is 8 because its basically saying 40m every second divide by acc.(gravity) which is basically 10 and multiply by 2 one second going up and another going down. but I am completely lost on the first part

The Attempt at a Solution



im not sure but i think i use the formula for displacement? but when i tried the answer was wrong.
 
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Write the three motion equations here. And then see what you are looking for.
What is the final velocity?
What is initial velocity?
What is distance? - not known
What is time? - not given
What is acceleration?

You should try equation with time in it when finding the distance.
 

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