Solving Three Charges: Find Force on Q2

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To find the total force on charge Q2, the correct approach involves using the force equation F=kq1q2/r^2 for both interactions with Q1 and Q3, considering their directions. The forces from Q1 and Q3 must be treated as vectors, meaning their signs (direction) must be accounted for when summing them. Since Q1 and Q3 are both positive, their forces on Q2 will act in opposite directions, which affects the total force calculation. The initial calculation of 5.29 N is incorrect due to not properly considering the vector nature of the forces. Correctly applying these principles will yield the accurate total force on Q2.
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Homework Statement


Three charges, Q1, Q2, and Q3 are located in a straight line. The position of Q2 is 0.323 m to the right of Q1. Q3 is located 0.125 m to the right of Q2
In the above problem, Q1 = 1.37 μC, Q2 = -2.53 μC, and Q3 = 3.43 μC. Calculate the total force on Q2. Give with the plus sign for a force directed to the right.


Homework Equations



F=kq1q2 / r^2

The Attempt at a Solution


I used the above formula to find the force for charge 1-2, and charge 2-3, and then added them together. I got the wrong answer.
My answers were: 0.29867 N + 4.99 N = 5.29 N
What am i doing wrong !?
 
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jmatthews1991 said:

Homework Statement


Three charges, Q1, Q2, and Q3 are located in a straight line. The position of Q2 is 0.323 m to the right of Q1. Q3 is located 0.125 m to the right of Q2
In the above problem, Q1 = 1.37 μC, Q2 = -2.53 μC, and Q3 = 3.43 μC. Calculate the total force on Q2. Give with the plus sign for a force directed to the right.


Homework Equations



F=kq1q2 / r^2

The Attempt at a Solution


I used the above formula to find the force for charge 1-2, and charge 2-3, and then added them together. I got the wrong answer.
My answers were: 0.29867 N + 4.99 N = 5.29 N
What am i doing wrong !?

Q1 and Q3 are both positive, but on opposite sides. Would their forces add?
 
berkeman said:
Q1 and Q3 are both positive, but on opposite sides. Would their forces add?

I added them
 
jmatthews1991 said:
I added them

And got the wrong answer...
 
berkeman said:
And got the wrong answer...

Yeah I got the wrong answer.. What did I do wrong? What should I do ?
 
jmatthews1991 said:
Yeah I got the wrong answer.. What did I do wrong? What should I do ?

The force equation that you wrote in your original post (OP) is actually a vector equation. The forces have both magnitude and direction. You need to take that into account when you sum the forces to get the resultant.
 
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