Solving Torque: R=9cm, F=18N, d=30cm

  • Thread starter Thread starter ohheytai
  • Start date Start date
  • Tags Tags
    Torque
AI Thread Summary
The torque exerted about the center of a disk with a radius of 9 cm, pulled by a force of 18 N, is calculated using the formula τ = R * F. The correct calculation yields τ = 0.09 m * 18 N, resulting in a torque of 1.62 N*m. Despite the initial confusion, the distance unwound (30 cm) does not affect the torque calculation since the force is applied tangentially. The final answer is confirmed as <0,0,-1.62> N*m. Understanding the direction and application of the force is crucial for accurate torque calculations.
ohheytai
Messages
81
Reaction score
0
what is the torque??

A disk of radius R = 9 cm is pulled along a frictionless surface with a force of F = 18 N by a string wrapped around the edge.


At the instant when d = 30 cm of string has unwound off the disk, what is the torque exerted about the center of the disk?



i tried \tau = R*F but it did not work can someone help me?
 
Physics news on Phys.org


ohheytai said:
i tried \tau = R*F but it did not work can someone help me?
Seems right to me. Show exactly what you did.
 


i did .09m*18N and got 1.62 N*m but its wrong
 


ohheytai said:
i did .09m*18N and got 1.62 N*m but its wrong
Is the string tangent to the disk or at an angle?
 


tangent
 


ohheytai said:
tangent
Then I'd say that you answer is correct.

Post the entire problem including any diagrams.
 


okay here it is
 

Attachments

  • WA.jpg
    WA.jpg
    17.9 KB · Views: 1,185


I'd say your answer is correct. The distance is irrelevant.

Is this a stand alone problem or just one part of a longer problem?
 


stand alone.
 
  • #10


ohheytai said:
i did .09m*18N and got 1.62 N*m but its wrong

the answer is <0,0,-1.62> N*m lol :)
 
Back
Top