Solving Train Collision: Min Rate, Collision Speed & Distance Traveled

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SUMMARY

The discussion centers on calculating the minimum deceleration required for a passenger train traveling at 30 m/s to avoid colliding with a freight train moving at 5.9 m/s, positioned 336 m ahead. The minimum constant deceleration determined is 0.887 m/s², based on the engineer's reaction time of 0.36 seconds. For a longer reaction time of 0.79 seconds, the approach speed of the passenger train at the moment of collision needs to be calculated, along with the distance traveled during the reaction time. The equations of motion used include x = x₀ + v₀t + 1/2 at² and v = v₀ + at.

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ts21121
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A passenger train is traveling at 30 m/s when the engineer sees a freight train 336 m ahead of his train traveling in the same direction on the same track. The freight train is moving at a speed of 5.9 m/s.

1.If the reaction time of the engineer is 0.36 s, what is the minimum (constant) rate at which the passenger train must lose speed if a collision is to be avoided?

2. If the engineer's reaction time is 0.79 s and the train loses speed at the minimum rate described in Part (a), at what rate is the passenger train approaching the freight train when the two collide?


For both reaction times, how far will the passenger train have traveled in the time between the sighting of the freight train and the collision?

x=x0+v0t +1/2 at2
v=v0+at



The Attempt at a Solution


for part 1 i know the answer is .887m/s^2.
after this i am completely lost on how to solve for part 2 and 3
 
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Hi ts21121, welcome to PF.
I am getting slightly different answer for the part 1. Will you show your calculations?
 

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