Solve sin^2(x) = cos^2(x) over the interval [0,2pi]
The Attempt at a Solution
sin^2(x) = cos^2(x)
sin^2(x) = 1-sin^2(x)
2sin^2(x) = 1
sin^2(x) = 1/2 = pi/6
sin(x) = sq root 1/2 = sq root pi/6
Unfortunately I am completely lost at this point and am not sure if I did that part correctly. If I did where would I go from here? Any help would be greatly appreciated, including any books where I could find some examples of whatever (or what) this is. Regardless, thank you for your time.