Welcome to PF,FiskiranZeka said:Can you explain me the steps of solving this problem and write the process/calculation ?
Thank you very much.
Everything looks good up until this point. Your next statement is incorrect:FiskiranZeka said:You are asking how i treid to solve this right ?
So, i explain;
q=V.C
3C + C --> 4C
q = 4C. V1
On the Upper Wire, there is 10 Voltage
On the Upper Wire, there is Tottal 4C + 1C --> 4/5 C
On the Upper Wire,
Q= 4C.V1 or 4/5C.Vtotal
( Vtotal = 10 Volt )
So, V1= 2 Volt,
V1/V2 = 1/4
So V2=8 Volt,
On the downside Wire,
above Cx is 8 Voltage,
So above 2C must be 2 Voltage, because 2+8 = 10 Volt ( Total Voltage )
q on the downside wire is;
q= V2.Cx or q = 2C. ( Voltage of 2C )
So, V2.Cx = 2C. ( Voltage of 2C )
V2 = 8 Volt,
8.Cx = 2C . 2Volt
Picking up from your previous like you have:Cx = 1/2
After discussing this problem with another Homework Helper, we both agree that the correct answer is Cx = 1/2*C as you have.FiskiranZeka said:Yeah sorry,
my calculations say -->
Cx = 1/2 C
But correct answer is Cx = 8C
As the answer has Unknown Capacitance (C) too...
We don't need to eliminate C...
No problem... Just need to find how many C is equal to Cx.
Hootenanny said:After discussing this problem with another Homework Helper, we both agree that the correct answer is Cx = 1/2*C as you have.
Wherever you got the 'correct' answer of Cx = 8*C is incorrect.