Solving Voltage Capacitors: Step-by-Step Guide

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    Capacitors Voltage
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The discussion focuses on solving a voltage capacitor problem using the formula q=V.C. The participant outlines their calculations, arriving at a conclusion that Cx = 1/2 C, while initially believing the answer was Cx = 8C. After further discussion, it is confirmed that the correct answer is indeed Cx = 1/2 C, despite conflicting information from a physics book. The conversation emphasizes the importance of verifying calculations and understanding the underlying principles of capacitor voltage relationships. The problem is ultimately resolved with clarity on the correct capacitance value.
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Capacitors - Voltage [ Solved ]

Can you explain me the steps of solving this problem and write the process/calculation ?
Thank you very much.
 

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FiskiranZeka said:
Can you explain me the steps of solving this problem and write the process/calculation ?
Thank you very much.
Welcome to PF,

That's not the way it works here. We will help you through your homework, but we won't do it for you.

What have you tried thus far?
 
You are asking how i treid to solve this right ?
So, i explain;

q=V.C

3C + C --> 4C
q = 4C. V1

On the Upper Wire, there is 10 Voltage
On the Upper Wire, there is Tottal 4C + 1C --> 4/5 C
On the Upper Wire,
Q= 4C.V1 or 4/5C.Vtotal
( Vtotal = 10 Volt )
So, V1= 2 Volt,
V1/V2 = 1/4
So V2=8 Volt,
On the downside Wire,
above Cx is 8 Voltage,
So above 2C must be 2 Voltage, because 2+8 = 10 Volt ( Total Voltage )
q on the downside wire is;
q= V2.Cx or q = 2C. ( Voltage of 2C )
So, V2.Cx = 2C. ( Voltage of 2C )
V2 = 8 Volt,
8.Cx = 2C . 2Volt
Cx = 1/2 is the wrong answer, what i have found...
 
FiskiranZeka said:
You are asking how i treid to solve this right ?
So, i explain;

q=V.C

3C + C --> 4C
q = 4C. V1

On the Upper Wire, there is 10 Voltage
On the Upper Wire, there is Tottal 4C + 1C --> 4/5 C
On the Upper Wire,
Q= 4C.V1 or 4/5C.Vtotal
( Vtotal = 10 Volt )
So, V1= 2 Volt,
V1/V2 = 1/4
So V2=8 Volt,
On the downside Wire,
above Cx is 8 Voltage,
So above 2C must be 2 Voltage, because 2+8 = 10 Volt ( Total Voltage )
q on the downside wire is;
q= V2.Cx or q = 2C. ( Voltage of 2C )
So, V2.Cx = 2C. ( Voltage of 2C )
V2 = 8 Volt,
8.Cx = 2C . 2Volt
Everything looks good up until this point. Your next statement is incorrect:
Cx = 1/2
Picking up from your previous like you have:

8C_x = 4C

Hence,

C_x = \frac{1}{2}{\color{red}\bold{C}}

You still need to eliminate the unknown Capacitance (C). Do you follow?
 
Yeah sorry,
my calculations say -->
Cx = 1/2 C

But correct answer is Cx = 8C

As the answer has Unknown Capacitance (C) too...
We don't need to eliminate C...
No problem... Just need to find how many C is equal to Cx.
 
FiskiranZeka said:
Yeah sorry,
my calculations say -->
Cx = 1/2 C

But correct answer is Cx = 8C

As the answer has Unknown Capacitance (C) too...
We don't need to eliminate C...
No problem... Just need to find how many C is equal to Cx.
After discussing this problem with another Homework Helper, we both agree that the correct answer is Cx = 1/2*C as you have.

Wherever you got the 'correct' answer of Cx = 8*C is incorrect.
 
Hootenanny said:
After discussing this problem with another Homework Helper, we both agree that the correct answer is Cx = 1/2*C as you have.

Wherever you got the 'correct' answer of Cx = 8*C is incorrect.

Yeayy ! Thank you !
I have also doubt that 8C Could be wrong, but i couldn't be sure, 'cos it's Physic Book's answer. Anyway, now I am glad :))

// Problem Solved.
 
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