Solving Wave Propagation Dilemma: Length Increase of 10%

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Homework Help Overview

The problem involves wave propagation along a string or spring, specifically examining the effects of a 10% increase in length on the time it takes for a wave to travel the length of the medium. The discussion centers around the relationship between tension, length, and wave speed.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants explore the implications of increasing the length of the string and how it affects tension and wave speed. Questions arise regarding whether the tension in the string increases or decreases with lengthening, and how this impacts the wave's travel time.

Discussion Status

The discussion is active, with participants sharing different interpretations of how the increase in length affects the system. Some express confusion about the relationship between force, tension, and wave speed, while others provide insights based on the equations of motion for waves.

Contextual Notes

There is some ambiguity regarding the assumptions about tension and mass per unit length as the string is stretched. Participants note that the problem does not explicitly state changes in force or tension, leading to varied interpretations of the physical scenario.

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Homework Statement



A wave takes 4s to travel form one end of the string to the other. Then the length is increased by 10%. Now how long does a wave take to travel the length of the spring?

Homework Equations



v = sqrt ( FL/m)
F = -kx

The Attempt at a Solution



If the original stretch was x, then an increase of ten percent would be:
1.1x.

So, if F = -kx, and since k is constant, if x increases by a factor of 1.1, then as does F. SO the tensional force is 1.1F the original.

v = sqrt ( 1.1F*L/m)
(delta d) / (delta t) = sqrt ( 1.1F*L/m)
taking the inverse:
(delta t) / (delta d) = sqrt ( m/1.1F*L)

where (delta d = 1.1L) since it has increased by ten percent.

So,

delta t = 1.1L*sqrt ( m/1.1F*L)
so the original delta t must increase by a factor of 1.1/sqrt(1.1)

?

?
 
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So, if F = -kx, and since k is constant, if x increases by a factor of 1.1, then as does F.
I don't understand this. The question doesn't say anything about the force or tension changing. Making the string longer might DEcrease the force but it sure wouldn't increase it.
 
It's actually a spring, but I was under the impression if you stretched a spring, you increased the tension..
 
Oh, sorry - I was thinking of putting a longer string on a guitar!

Using "v = sqrt ( FL/m)", it would appear that F increases by 1.1 and L increases by 1.1.
So the new v is 1.1 times the old v.
 
I was under the impression that L/m was a constant, regardless of whether it was stretched, since m/L is the linear mass density.
 
so L is the length? If so, L increases by a factor of 1.1, doesn't it?
The mass per unit length would decrease when the length increases.
 
I came here because apparently the velocity does not change.. I don't get how it doesn't change, though/
 
Oh, that's the answer I got! Using L increases by a factor of 1.1 and v increases by a factor of 1.1 in the formula t = d/v.
 
lol ill check it out thanks
 

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