Some one me with the derivation

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The discussion centers on deriving the acceleration of block 2 (m2 = 1.3 kg) in a frictionless pulley system, with the relationship between the accelerations of block 1 (m1) and block 2 established as a2 = 1/2 a1. The user attempts to derive an expression for a2, leading to the equation a2 = m2g/(4m1 + m2). There is some confusion regarding the correct placement of the gravitational constant g in the equation, but it is clarified that both forms are mathematically equivalent. The conversation also highlights the importance of accurately identifying forces acting on the blocks, specifically gravity and tension. Overall, the derivation process and the relationships between the blocks are the main focus of the discussion.
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Homework Statement


In figure, the pulleys and the cod are light, all surfaces are frictionless, and the cord does not
stretch.
a) How does the acceleration of block 1 compare with the acceleration of block 2?
The mass of block 2 is m2 = 1.3 kg. Derive an expression for the acceleration of the
block having mass m2 as a function of the mass of block 1, m1.


Homework Equations


mg-T=m2a2
T=m1a1=m12a2



The Attempt at a Solution



The first one (a) i have done.
Which is that due to the pulley the acceleration of a2=1/2 a1

Can some one help me with the b part
 

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Hi lioric. Is there supposed to be a diagram to accompany this?
 


sorry i was in a rush and forgot
now its there
 


This is what i got for the derivation. But something is not right
 


Mass 2 equation
The pulley give 2 tensions so 2T
m2g-2T=m2a2

Mass 1 equation

T=m1a1
since a2 = 1/2a1
a1= 2a2

T=m12a2

substitute mass 1 equation in mass 2 equation as T

m2g-2(2m1a2)=m2a2
m2g-4m1a2=m2a2

make subject a2

-4m1a2-m2a2=-m2g
change negative sign by multiplying by -1

4m1a2+m2a2=m2g

a2(4m1+m2)=m2g

a2=m2g/4m1+m2

But i feel that this is not right.
 


lioric said:
In figure, the pulleys and the cod are light, all surfaces are frictionless, and the cord does not stretch.
It's cog, not cod.
mg-T=m2a2
That equation is not correct. What are all the forces on m2?
 


m2 would have gravity and tension
 


haruspex said:
It's cog, not cod.
I believe it's c-o-r-d
 


ok enough about the "CORD"

m2 would have gravity and tension those are the forces on M2

so what's next?
 
  • #10


lioric said:
The pulley give 2 tensions so 2T
m2g-2T=m2a2
That's better (your post crossed with mine).
a2=m2g/4m1+m2
Looks ok to me, if parentheses inserted:
a2=m2g/(4m1+m2). What bothers you?
 
  • #12
lioric said:
It shows the answer where g is out side a bracket. mine is in the numerator
The two are equivalent.
 
  • #13
ok thank you
 
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