How Do Different Aperture Shapes in a Styrofoam Box Affect Wave Harmonics?

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The experiment involved placing a speaker in a styrofoam box with variously shaped holes to study their impact on wave properties. Different hole shapes, such as funnels and squares, influenced the waveform shapes produced, resulting in sinusoidal, triangular, and square waveforms. The researcher seeks methods to compare the harmonics generated by each block shape. Key considerations include measuring the spatial dimensions of the waves and how they relate to the dimensions of the apparatus. Understanding these relationships is crucial for analyzing the effects of aperture shapes on wave harmonics.
arianna1012
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I did an experiment for school, and I put a speaker in a styrofoam box with a rectangle cut out of the front. I had styrofoam bricks that fit perfectly in the hole, each with a hole cut out. The hole shape differed, with things like a funnel, a diagonal line, a circle, a square, etc. I was trying to see if it effected the property of the wave, like wavelength, frequency, etc., but after getting my data I realized it actually effected the shape of the wave. Some are sinusoidal, but others have more of a triangle or even a square shape. I know this is caused by the harmonics, but I need to figure out a way to compare the harmonics from a certain block to the other blocks. How do I do this?
 
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The only thing that varies with different shaped holes is the scale of the spatial dimensions. How would you measure the spatial dimensions of a wave and how does it compare to the spatial dimensions of the apparatus?
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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