Soup Can Kinetics: Calculating Accelerating Force

  • Thread starter Thread starter mrsmed
  • Start date Start date
  • Tags Tags
    Kinetics
mrsmed
Messages
1
Reaction score
0

Homework Statement



mass of can .298 kg length of table 1.257 m height of elev .05m

time trial 1 3.50 sec 2 4.22 sec 3 4.23 sec
length of table


determine the force required to accelerate the can along the table. avg speed is .36 m/s final speed is .72 m/s acceleration is 1.257m/3.98 s = .32 m/s how do i find accelerating force

Homework Equations


i found acceleration how to i find accelerating force ? is the 9.80 m/s come into play somewhere?


The Attempt at a Solution

 
Physics news on Phys.org
Welcome to PF!

mrsmed said:
acceleration is 1.257m/3.98 s = .32 m/s how do i find accelerating force

Hi mrsmed! Welcome to PF! :smile:

Use good ol' Newton's second law …

force = mass times acceleration :smile:
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top