Space probe between the earth and moon

AI Thread Summary
To determine the point where the net gravitational force on a space probe between the Earth and the Moon is zero, the gravitational forces from both bodies must be equal. The equation derived indicates that the mass of the Earth and Moon, along with their distances from the probe, must balance out. For the energy required to lift the probe to the Moon's surface, it's essential to consider the gravitational potential energy and the influence of the Moon's gravity, which reduces the total work needed. The escape velocity calculation is not directly relevant to the energy required for this specific task. Understanding these gravitational interactions and energy calculations is crucial for accurate results.
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Homework Statement



The mass of the Earth is Me and the mass of the Moon is Mm. The (center to center) Earth to moon distance is d.
a) If a space probe is sent directly from the Earth to the moon, how far from the center of the Earth would the net gravitational force (due to the Earth and moon) on the probe be zero?
b) Neglecting friction, how much net energy would it take to lift a space probe from the surface of the Earth to the moons surface?

Homework Equations


E = K + U

F = G\frac{Mm}{r^2}

The Attempt at a Solution



a) There are two forces acting on the probe, the force of gravity of the moon and the force of gravity of the earth. We are trying to find the distance where the combination of these two forces is 0 so:

M_e = mass of Earth M_m = mass of moon M_p = mass of probe d = Earth to moon distance r = Earth to probe distance

F_{moon} - F_{earth} = 0

F_{moon} = F_{earth}

G\frac{M_m M_p}{(d-r)^2} = G\frac{M_e M_p}{r^2}

\frac{M_m}{(d-r)^2} = \frac{M_e}{r^2}

It seems I have hit a wall. How can I isolate r? b)

since we need the satellite to escape Earth's orbit we need to find the escape velocity. this happens when the satellite goes to infinity with a speed of 0.

\frac{v_{esc}^2}{2} - G\frac{M_e}{r_e} = 0 + 0 \frac{v_{esc}^2}{2} = G\frac{M_e}{r_e}

v_{esc} = (2G\frac{M_e}{r_e})^\frac{1}{2}

now we need to find the energy needed

W + \frac{v_{esc}^2}{2} - G\frac{M_e}{r_e} = 0

W = - \frac{v_{esc}^2}{2} + G\frac{M_e}{r_e}

would this give the correct answer?
 
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a) Try inverting the equation and then expand the d-r term; then find the roots of the equation.

b) The question didn't ask for the escape velocity, so I think you should drop this term; however, you need to account for the fact that the moon will reduce the work required because it attracts the satellite.
 
Your method in part b) appears to guarantee the answer W = 0.
Since it asks for net energy, you need to take into account the potential energy when on the surface of the moon.
 
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