Spatial Frequencies of the Fourier Transform

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The Fourier Transform converts a spatial function into its frequency representation, with spatial frequencies denoted as ##p## and ##q##. To obtain these frequencies, the function must be sampled ##N## times with a sampling interval ##\Delta x##, leading to a frequency resolution of ##2\pi/N\Delta x##. The Nyquist frequency defines the boundaries of the frequency domain, which is crucial for accurate analysis. Additionally, spatial frequencies are often referred to as wavenumbers, defined as ##k = 2\pi/\lambda##. Understanding these concepts is essential for effective numerical simulations involving Fourier Transforms.
ecastro
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The Fourier Transform transforms a function of space into a function of frequency. Considering a function ##f\left(x, y\right)##, the Fourier Transform of such a function is ##\mathcal{F}\left\{f\left(x, y\right)\right\} = F\left(p, q\right)##, where ##p## and ##q## are the spatial frequencies.

In numerical simulations, the function ##f## can easily be transformed by using an algorithm (built-in in the software). However, I am concerned on acquiring the spatial frequencies ##p## and ##q##. Is there a way to do it?

Thank you in advance.
 
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If the function in space domain is sampled ##N## times with sampling interval ##\Delta x##, then the frequency resolution in the frequency domain is given by ##2\pi/N\Delta x##.
 
blue_leaf77 said:
If the function in space domain is sampled ##N## times with sampling interval ##\Delta x##, then the frequency resolution in the frequency domain is given by ##2\pi/N\Delta x##.
I don't know if I got this right. Is the value of ##N## the number of points, ##\Delta x## is the interval between two adjacent points, and the interval between two points in the frequency domain is ##\frac{2 \pi}{N \Delta x}##?
 
ecastro said:
I don't know if I got this right. Is the value of ##N## the number of points, ##\Delta x## is the interval between two adjacent points, and the interval between two points in the frequency domain is ##\frac{2 \pi}{N \Delta x}##?
Yes, exactly.
 
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Thank you.

I have another question, how will I know the boundaries (maximum and minimum values) of the frequency domain?
 
I'll also throw in that a "spatial frequency" is more commonly called a "wavenumber".
 
boneh3ad said:
I'll also throw in that a "spatial frequency" is more commonly called a "wavenumber".

The wavenumber of what? What is ##\lambda## in this case?
 
ecastro said:
The wavenumber of what? What is ##\lambda## in this case?
The wavenumber of "whatever the spatial frequency belongs to."

The usual way of defining the wavenumber is exactly analogous that for frequency:
##k = 2\pi/\lambda## in radians per length, or ##\nu = 1/\lambda## if the units are cycles per length.
 

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