Special relativity help: meter stick moving at 0.60c

AI Thread Summary
When a meter stick moves at 0.60c, its length contracts due to the effects of special relativity, leading to a measured length L that falls within the range of 0.80 m to 1.0 m. The calculation of gamma (γ) confirms that length contraction occurs, but the range arises because the observer's measurement depends on the relative velocity between the observer and the meter stick. The meter stick's proper length is 1 m when at rest, but as it approaches relativistic speeds, its length appears shorter to the observer. This range reflects the variability in measurements based on different relative velocities and the principles of length contraction. Understanding these concepts clarifies why the length of the moving meter stick is not fixed but varies within specified limits.
positron
Messages
21
Reaction score
0
A meter sticks moves with velocity 0.60c relative to an observer. The observer measures the length of the meter stick to be L. The problem states that 0.80<L<1.0 m must always be true.
So far, I have determined that
Gamma = 1/sqrt(1-0.60c^2/c^2) = 0.8.
What I don't understand is why there is a range. If the meter stick is 1 m when it is not moving and 0.8m when it is moving at 0.80c, why is there a range for the length?
 
Physics news on Phys.org
Is velocity a vector?
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top