Special Relativity spaceship problem

AI Thread Summary
The discussion revolves around a problem in special relativity involving a spaceship traveling at 0.99c relative to Earth and a laboratory measuring 56.4m in length. The spaceship crew measures the lab's length using the concept of length contraction, which states that objects moving relative to an observer will appear shorter. The proper length is defined as the length measured in the object's rest frame, meaning the Earth’s frame is the proper frame for the lab. A participant initially misapplied the length contraction formula but was corrected, emphasizing that the spaceship crew will measure the lab's length as less than 56.4m. Understanding the proper length and the effects of relative motion is crucial in solving such problems in special relativity.
Taylor_1989
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Homework Statement


You are on Earth as a spaceship flies past at a speed of 0.99c relative to the earth. A high-intensity signal light on the ship blinks on and off, each pulse lasting 2.2 × 10^(−6) s, as measured on the spacecraft .

Your laboratory on Earth has a length of 56.4m. How long does the spaceship crew measure it to be?

Homework Equations


length contraction

The Attempt at a Solution


So I am viewing the question like this. If I am standing on the spaceship as this is my frame of ref; right? The the proper length would be unknown as proper length is only measure when me for example is at rest, so I the thought that if I am at rest on the ship the Earth is moving 0.99c relative to me, therefore I transposed the length contraction formula to get my ans.

L_0= proper length
L= length on Earth

so If I use the length contraction formula to solve for L_0 I would get what the i view it on the space ship, is this correct?

my ans was 59.8m from space ship.

Very new to special relativity so still getting my head round it.
 
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You have it backwards. The proper length of the lab is the length measured in its rest frame, which is the Earth's frame. The spaceship crew will measure that length to be less.
 
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