Special Relativity with 2 light beams moving towards each other

AI Thread Summary
In the discussion about the relative speed of two light beams moving towards each other, a participant attempts to use the relativistic velocity addition formula. They calculate the speed as (c + c) / (1 + c^2/c^2), which simplifies incorrectly to 2c. The consensus is that no information can travel faster than the speed of light, c, leading to the conclusion that the left-moving beam approaches the right-moving beam at speed c from its perspective. The correct interpretation emphasizes that, regardless of the observer's frame, the speed of light remains constant at c. Understanding this principle is crucial for solving problems in special relativity.
Felipe Doria
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Homework Statement



If one light beam is heading toward you from the right, and another is heading toward you from the left, how quickly from the perspective of the right-moving beam is the left-moving beam approaching it?

1) 0
2) c
3) 1.5c
4) 2c

Homework Equations



(v+w) / (1 + cw/c2)

The Attempt at a Solution



I tried plugging in c into the equation for both v and w but it gives me (c + c) / (1 + c2/c2) which equals 2c. It is one of the possible answers but I know nothing can go faster than c so I'm thinking the answer is probably c. Am I right? If so, why? If not, what am I doing wrong?
 
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Felipe Doria said:

Homework Statement



If one light beam is heading toward you from the right, and another is heading toward you from the left, how quickly from the perspective of the right-moving beam is the left-moving beam approaching it?

1) 0
2) c
3) 1.5c
4) 2c

Homework Equations



(v+w) / (1 + cw/c2)

The Attempt at a Solution



I tried plugging in c into the equation for both v and w but it gives me (c + c) / (1 + c2/c2) which equals 2c. It is one of the possible answers but I know nothing can go faster than c so I'm thinking the answer is probably c. Am I right? If so, why? If not, what am I doing wrong?

(c+c)/(1+c^2/c^2) isn't equal to 2c.
 
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