Spectral lines and energy levels

Pika007
Messages
2
Reaction score
0

Homework Statement


In the spectrum depicted bellow (see added picture) are spectral lines which resulted from emissions of a photon due to an electron decaying from a higher to a lower orbital in a Hydrogen-like atom (meaning- only one electron. No details about the nucleus)
All lines in the given spectrum are a result of an electron decaying for an excited state to the first excited state. The wavelength of line C is 48.214nm, Calculate the energy of a photon co-responding to line D.


Homework Equations



v=c/f
E(ph)= hv
Reidberg's equation (too complicated to type in)

The Attempt at a Solution



Our presentation didn't include any similar example, so I'm at a loss about how to approach this. Been staring at the page for a better part of the day.
Any help would be much appreciated
 

Attachments

  • spectrum.jpg
    spectrum.jpg
    6.9 KB · Views: 675
on Phys.org
The Rydberg formula for hydrogen-like atoms is:
[itex]\frac{1}{\lambda}=RZ^{2}(\frac{1}{n^{2}_f}-\frac{1}{n^{2}_i})[/itex]
Since the graph constitutes the entire spectrum for any [itex]n_i\rightarrow2[/itex] transition with [itex]n_i>2[/itex], where [itex]n_f=2[/itex] for any transition (since [itex]n=2[/itex] for the first excited state).
Notice that A corresponds to transition [itex]3\rightarrow2[/itex], B corresponds to [itex]4\rightarrow2[/itex] and so on, hence you can figure out which transitions correspond to lines C and D respectively.
 
ok, this clarified some things up, especially explaining the transitions.

EDIT-
thanks, i got it. Also managed to understand things properly along the way.
 
Last edited:

Similar threads

Replies
0
Views
2K
  • · Replies 21 ·
Replies
21
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
Replies
16
Views
3K
  • · Replies 12 ·
Replies
12
Views
2K
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
7
Views
3K
  • · Replies 10 ·
Replies
10
Views
2K
Replies
8
Views
5K