Speed of a wave on a string w.r.t. which reference frame

Click For Summary

Discussion Overview

The discussion revolves around the speed of a wave on a string, specifically questioning the reference frame from which this speed is measured. Participants explore the implications of the wave speed formula, v = √(τ/μ), and its dependence on reference frames, as well as comparisons to the speed of light in different media.

Discussion Character

  • Debate/contested
  • Technical explanation
  • Conceptual clarification

Main Points Raised

  • One participant asserts that the speed of a wave in a string is given by v = √(τ/μ) and questions whether this speed is independent of reference frame, citing experimental observations that contradict this notion.
  • Another participant clarifies that the speed is measured with respect to the frame in which the string is at rest.
  • Some participants express confusion about the derivation of the wave speed equation and the assumptions made during this derivation.
  • A participant draws a parallel between the speed of light in a medium and the wave speed in a string, suggesting that both should be independent of reference frames due to the properties of the medium.
  • Others challenge this view, explaining that relativistic velocity addition must be considered when the medium is in motion relative to an observer.
  • Several participants discuss the concept of spacetime and its relevance to the propagation of light, with some expressing misunderstanding of the term.
  • There is a request for clarification on how to modify the wave equation to account for different reference frames when calculating the speed of light in a moving medium.
  • One participant notes that many derivations do not explicitly mention reference frames, assuming the context makes it clear that the string is at rest.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the implications of the wave speed formula with respect to reference frames. Multiple competing views remain regarding the independence of wave speed from reference frames and the application of relativistic velocity addition.

Contextual Notes

Participants highlight the importance of understanding the assumptions underlying the derivation of the wave speed equation and how these assumptions may affect the interpretation of results in different reference frames.

Who May Find This Useful

This discussion may be of interest to those studying wave mechanics, relativity, and the properties of light in various media, particularly in understanding the nuances of reference frames in physics.

Pushoam
Messages
961
Reaction score
53
Speed of a wave in a string is given by √(τ/μ) .
But this speed is with respect to which reference frame?
Since, the speed depends on τ and μ( which are independent of reference frame ), I can consider speed of wave independent of reference frame.
But this is not so. From experiment, we know that if the Speed of a wave in a string is v = √(τ/μ) with respect to string ,then with respect to a reference frame moving with speed v with respect to string along the direction of wave propagation, the wave's speed will be 0 m/s.
So, experimentally , I can't consider speed of wave independent of reference frame.
Can anyone please resolve this contradiction?
 
Physics news on Phys.org
It's the speed with respect to the frame of reference in which the string is at rest.
 
pixel said:
It's the speed with respect to the frame of reference in which the string is at rest.
This is what I said here
Pushoam said:
From experiment, we know that if the Speed of a wave in a string is v = √(τ/μ) with respect to string
I want to know what is wrong with the following argument?
Pushoam said:
Since, the speed depends on τ and μ( which are independent of reference frame ), I can consider speed of wave independent of reference frame.
 
Pushoam said:
I want to know what is wrong with the following argument?
How was the equation derived? What assumptions were made in the derivation of the equation?
 
Speed of light in a medium depends on the electric and magnetic properties of the medium i.e. mu and epsilon and since these properties do not depend upon the frame , speed of light in medium should be independent of frames.
Is this so?
If speed of light depends on the frames ,then does the wave equation imply it ?
 
Pushoam said:
Is this so?

Yes, but not for the reason you give. Spacetime is not a "medium", and the "electric and magnetic properties of the medium" you refer to are artifacts of a particular choice of units, not physical properties of anything. The speed of light is frame independent because, like ##\mu_0## and ##\epsilon_0##, it is really just an artifact of a particular choice of units; it is a conversion factor between our choice of time units and our choice of distance units, because we did not, historically, use the same units for these things. In "natural" units, the speed of light is ##1##.
 
Pushoam said:
speed of light in medium should be independent of frames.
As PeterDonis says, spacetime is not a medium. But with that said... Yes, the speed of light in a medium relative to the medium is indeed frame-independent, and this does follow from the frame-independent values of the permittivity and permeability of the medium.

However, relativistic velocity addition still applies. If the speed of light relative to the medium is ##u## and the medium is moving at speed ##v## in some frame, then in that frame the light will be moving at speed ##(u+v)/(1+uv)## according to the relativistic velocity addition rule. This was first observed by Fizeau in 1851 when he was measuring the speed of light in moving water; his result was an underappreciated mystery until Einstein discovered relativity more than half-century later.
 
Nugatory said:
As PeterDonis says, spacetime is not a medium.
I don't understand "spacetime" and why are we using it here?
Nugatory said:
Yes, the speed of light in a medium relative to the medium is indeed frame-independent,
To illustrate the above quote using an example:
Let's say that I have two transparent boxes A and B filled with water .
B moves with speed v w.r.t. A along +ve x-axis.
light wave moves in both boxes along +ve x-axis.
Now , speed of light wave (which passes through A) w.r.t. A = speed of light wave (which passes through B) w.r.t. B
You say that this is true because of
Nugatory said:
the frame-independent values of the permittivity and permeability of the medium.
speed of light wave (which passes through B) w.r.t. A ≠ speed of light wave (which passes through B) w.r.t. B
Here,relativistic velocity addition applies.
This I don't understand.
According to me,
even if a person sitting on A wants to calculate speed of light passing through B, he will write the wave equation and he will get v = 1/(sqrt με) = speed of light wave (which passes through B) w.r.t. B
Why should relativistic addition come here when speed of light depends only on ε and μ and both of these are independent of frame?
 
Pushoam said:
even if a person sitting on A wants to calculate speed of light passing through B, he will write the wave equation and he will get v = 1/(sqrt με) = speed of light wave (which passes through B) w.r.t. B
That gives the speed of the light flash with respect to B. If B is moving with respect to A, then the speed of the light flash relative to A is given by the relativistic velocity addition formula.
 
  • #10
Pushoam said:
I don't understand "spacetime"

I apparently misunderstood your OP. "Spacetime" is a basic concept in relativity, and my post was talking about light propagation through vacuum, with no material medium present; under those conditions, the properties of spacetime are the only thing governing light propagation. However, you appear to be asking about the case where there is a material medium (like air or water) present; Nugatory's posts address that case.
 
  • #11
Nugatory said:
That's gives the speed of the light flash with respect to B. If B is moving with respect to A, then the speed of light relative to A
O.K.
So,if the person sitting on A wants to calculate speed of light passing through B,
1) just by using wave equation, what modification will he have to do in his wave equation? Is this a right approach?
I mean can he get (u+v)/(1+uv) as the speed of light from the wave equation itself?
2)or
The wave equation always gives speed of light only w.r.t. medium and so he should calculate speed of light w.r.t. medium i.e.B using wave equation and then apply relativistic velocity addition to get the speed of light w.r.t. his frame i.e. A.
 
  • #12
PeterDonis said:
I apparently misunderstood your OP.
Will you please tell me what is meant by OP?
 
  • #13
Pushoam said:
Will you please tell me what is meant by OP?

The Original Post in the thread.
 
  • #14
Moderators note: I merged your two threads about the invariance of the wave equation since they are fairly similar topics.

The recommendation that I gave you before still applies. What are the assumptions, and do those assumptions still hold?

Also, for EM you need to make sure that you understand how EM quantities transform between reference frames.
 
  • #15
Dale said:
The recommendation that I gave you before still applies. What are the assumptions, and do those assumptions still hold?
I am attaching here derivation of speed of wave in a string.
This is from University Physics , 12 th edition, Sears and Zemansky.
I don't see here any mention of reference frame or any assumption which will lead me to the answer of my question( post 1).
 

Attachments

  • #16
Pushoam said:
I am attaching here derivation of speed of wave in a string.
This is from University Physics , 12 th edition, Sears and Zemansky.
I don't see here any mention of reference frame or any assumption which will lead me to the answer of my question( post 1).
People often do not mention the reference frame in their derivations when it is obvious from the context which one they're using; I could pick up any first-year textbook and find hundreds of examples and exercises that don't mention a reference frame for every one that does. Here the context makes it clear that they're working in a frame in which the string is at rest.

So the answer to the question in your original post
Speed of a wave in a string is given by √(τ/μ) .
But this speed is with respect to which reference frame?
is the one that we've already given above: That will be the speed using a frame in which the string is at rest. The speed of the wave relative to an observer at rest in some other frame is calculated using the appropriate velocity addition rule.
 
Last edited:
  • #17
o.k.
Thank you.
 
  • #18
Pushoam said:
I am attaching here derivation of speed of wave in a string.
This is from University Physics , 12 th edition, Sears and Zemansky.
I don't see here any mention of reference frame or any assumption which will lead me to the answer of my question( post 1).
The file wouldn't open, so I cannot check this specific derivation. Most derivations explicitly assume that the material points on the string move only in the transverse direction. This implies that the velocity in the longitudinal direction is always 0. This condition is not met for a moving string.
 
  • #19
Dale said:
Most derivations explicitly assume that the material points on the string move only in the transverse direction. This implies that the velocity in the longitudinal direction is always 0. This condition is not met for a moving string.
O.K. Now I understood that while deriving the wave equation , it is assumed that the we are working in the reference frame in which the medium is at rest and so, the wave equation gives speed of the wave w.r.t. this reference frame.
Thank you.
Thank you, all for helping me to come to this conclusion.
 
  • Like
Likes   Reactions: Dale
  • #20
Dale said:
The file wouldn't open

In my laptop, it is opened.
By the way, leave it. Now it doesn't matter.
 

Similar threads

  • · Replies 236 ·
8
Replies
236
Views
17K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 19 ·
Replies
19
Views
2K
  • · Replies 25 ·
Replies
25
Views
3K
  • · Replies 18 ·
Replies
18
Views
2K
  • · Replies 3 ·
Replies
3
Views
5K
  • · Replies 17 ·
Replies
17
Views
3K
  • · Replies 33 ·
2
Replies
33
Views
3K
  • · Replies 55 ·
2
Replies
55
Views
4K
  • · Replies 19 ·
Replies
19
Views
10K