Speed of ball

  • Thread starter danosu43
  • Start date
  • #1
4
0
I've tried a few different equations but I'm not sure how to start this problem. I just realized I'm looking for the initial velocity since the speed of the ball is constant.

A bowling ball traveling with constant speed hits the pins at the end of a bowling lane 16.5 m long. The bowler hears the sound of the ball hitting the pins 2.45s after the ball is released from his hands. What is the speed of the ball?

Speed of sound=340 m/s
Bowling lane=16.5 m
Time till sound of ball heard=2.45s

This where I'm confused because I'm not sure which equations are the right ones to use.

Here is what I've attempted so far and I think I just realized its all wrong:

v=v(initial)+at
340 m/s=0+a(2.5s)
a=136m/s^2

(16.5m)/(2.45s)=6.73 s

I'm pretty sure this work is wrong but any help to start in the right direction would be much appreciated.
 

Answers and Replies

  • #2
751
37
The problem states that the ball is traveling at constant velocity so acceleration is not an issue. Knowing the speed of sound, figure out how long it took for the ball to hit the pins. Then knowing the time and distance of the lane you can find the velocity.
 
  • #3
4
0
If speed of sound=340 m/s then (16.5m)/(340m/s)=0.049s. Subtract that from 2.45s and it took the ball 2.401s to reach the pins and then 0.049s for the sound to return back to the person. Correct?
 
  • #4
4
0
Then the velocity=16.5m/2.401s which gives v=6.87 m/s
 
  • #5
751
37
Looks good to me
 

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