Speed of Block 3.5s After Start Moving | Conical Pendulum

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The discussion revolves around calculating the speed of a 3.46 kg block after 3.5 seconds of movement, given a pulling force of 13.9 N at a 26° angle and a kinetic friction coefficient of 0.09. The user struggles with determining the acceleration, initially calculating it as 0.8790 m/s². They have set up the equations of motion correctly, using the vertical and horizontal components of the tension and gravitational forces. Despite the calculations, the user expresses confusion about the results not aligning with expectations. The focus remains on resolving the speed calculation for the block under the specified conditions.
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A 3.46 kg block located on a horizontal floor is pulled by a cord that exerts a force F = 13.9 N at an angle theta = 26.0° above the horizontal, as shown in the Figure. The coefficient of kinetic friction between the block and the floor is 0.09. What is the speed of the block 3.5 s after it starts moving?

I'm having a bit of a problem with this. Mainly because I'm not sure how to answer the question. I got a decimal number less than 1 for the acceleration. Here are my two equations:

Y: T*sin(theta)-mg=0
X: F+T*cos(theta)=ma

a=.8790
 
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It's not centripetal motion, but I'm still having problems.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
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