Speed of Electrons: 1.13*10^6 m/s

AI Thread Summary
Two electrons, initially separated by 2*10^(-10)m and released from rest, will each reach a speed of 1.13*10^(6)m/s when they are a large distance apart. The problem involves converting the initial electric potential energy into kinetic energy as the electrons move apart. To solve it, one must calculate the initial electric potential energy using the elementary charge of the electrons. It is important to consider relativistic effects if the calculated speed approaches the speed of light. Understanding the conversion of potential energy to kinetic energy is crucial for finding the correct speed.
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Homework Statement



Two electrons separated by 2*10^(-10)m are released from rest. What is the speed of each electron when they are a large distance apart. (Both electrons will have the same speed.) The answer should be 1.13*10^(6)m/s.

Homework Equations



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The Attempt at a Solution



I am not sure what formula to use. If I were given kinetic energy I think I could figure this one out, but can't with the info given. Any help on where to start?
 
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The relevant equations are the equations for electrical potential energy and kinetic energy.
At a large distance apart, all of the potential energy stored at the start (when the e- are separated by 2*10^(-10) m) have been converted to kinetic energy.
 
Some large distance probably refers to infinite. Find the initial energy of the system, which would be the electric potential energy, U. At infinite, U would mostly convert to kinetic energy, K.

If your answer exceeds the speed of light (or comes considerably close), you might want to add relativistic adjustments.
 
Yes. I had forgotten to mention relativistic adjustments as well. Also keep in mind that the electron has an elementary charge (this will be useful when determining the electric potential energy.)
 
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