Not sure what you mean. Do you mean it cannot be checked analytically? It can. You would need to express the variable force as a function of x and integrate with respect to x to find the work done.PAstudent said:
Yes, but that says using "constant acceleration" kinematics. As you say, it is not constant acceleration. But it can be checked analytically by using kinematics that cope with variable acceleration because the nature of that variation is known exactly.PAstudent said:
The work-energy theorem states that the work done on an object is equal to the change in its kinetic energy. This means that when a force acts on an object to move it, the energy transferred is equal to the change in its motion.
According to the work-energy theorem, the work done on an object is equal to the change in its kinetic energy. This means that if the work done on an object increases, its kinetic energy will also increase, resulting in an increase in speed.
Yes, the work-energy theorem can be applied to all types of motion, whether it is linear, rotational, or a combination of both. As long as there is a force acting on an object and causing a change in its motion, the work-energy theorem can be used to analyze the situation.
The formula for calculating work using the work-energy theorem is W = ΔK = 0.5mv2f - 0.5mv2i, where W is work, ΔK is the change in kinetic energy, m is the mass of the object, vf is the final velocity, and vi is the initial velocity.
Yes, the work-energy theorem can be used to calculate the speed of an object if the mass and initial and final velocities are known. By rearranging the formula, vf = √(2W/m + vi2), the final speed of the object can be determined.