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Speedbump problem and center of velocity

  1. Mar 22, 2010 #1
    1. The problem statement, all variables and given/known data

    if a speedbump on a level road has the mathematical equation

    [tex]y = h/2 \cdot (1+cos(\pi \cdot x/b)) [/tex]

    where B is the length of the road covered by the bump.

    If a car starts a point G just before the bump at a speed v then supposedly

    the equation of the entire journey is

    [tex]y_G = 1/2 \cdot h/2 \cdot (1+cos(\pi \cdot x/b)) [/tex]

    What I don't get how do they arrive at that

    [tex]y_G = 1/2 \dot y[/tex]

    I am told its something with speed of center?

    What can I read more about that?
  2. jcsd
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