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if a speedbump on a level road has the mathematical equation

[tex]y = h/2 \cdot (1+cos(\pi \cdot x/b)) [/tex]

where B is the length of the road covered by the bump.

If a car starts a point G just before the bump at a speed v then supposedly

the equation of the entire journey is

[tex]y_G = 1/2 \cdot h/2 \cdot (1+cos(\pi \cdot x/b)) [/tex]

What I don't get how do they arrive at that

[tex]y_G = 1/2 \dot y[/tex]

I am told its something with speed of center?

What can I read more about that?

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# Homework Help: Speedbump problem and center of velocity

Can you offer guidance or do you also need help?

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