Spherically symmetric charge density

AI Thread Summary
The discussion focuses on solving a problem involving a spherically symmetric charge density defined as p(r)=Cr for r≤a and p(r)=0 for r>a. Participants are attempting to find the electric field E(r) and potential V(r), questioning their continuity at r=a. The use of Gauss's law is suggested for calculating the electric field, while the potential can be derived from the electric field. Additionally, the impact of placing extra charge uniformly on the surface at r=a is explored, with emphasis on determining continuity and the appropriate equations to use given the symmetry of the problem. The conversation highlights the complexity of the problem and the need for careful application of electrostatic principles.
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Homework Statement



Imagine a spherically symmetric charge density p(r)=Cr for r<=a, p(r)=0 for r>a.
a) Find the electric field E(r) and potential V(r). Are they continuous at r=a?
b) Suppose additional charge is placed uniformly on the surface at r=a with surface density sigma. Find E(r) and V(r). Are they continuous at r=a? Explain.

Homework Equations



gausses law

The Attempt at a Solution


[/B]
So for part a to find the electric field I think I integrate from 0 to r with the integrand being Cr4pi r^2 dr and then add the integral from 0 to a of 0*4 pi r ^2 dr. And i get Cpir^4 ? is this correct? How can I get the potential and to know if they are continuous? I am guessing they are not??

Also I am lost on part b - please help.
 
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Hm, I'd rather use the local laws, which are almost always so much more powerful than the integral laws.

Here, however, you can also use the integral law due to the very symmetric situation. Write down the relevant equation. You got already one side of this equation correct. Now you have to think about the other side of the equation, i.e., to check, which quantities you need and how you can get them from this equation, taking into account the spherical symmetry of the problem. Finally you can think about the potential.

Of course, there's also a direct solution for the electrostatic potential for a given static charge distribution, but the question sounds as if you should not ;-)).
 
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