Spring and Incline Plane (Conservation of Energy Problem)

AI Thread Summary
The discussion revolves around a physics problem involving a box sliding down a frictionless ramp and colliding with a spring. The maximum compression of the spring is determined using energy conservation principles, yielding a correct answer of 2.5 m. For the second part of the problem, which seeks the compression at maximum speed, the user initially struggles but is advised to consider the net forces acting on the box. It is clarified that the approach of equating spring force to gravitational force is valid only in static equilibrium, not for an accelerating object. The distinction between the two scenarios is crucial for solving the problem accurately.
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Homework Statement


MP: 10.71
A 25 kg box slides 4.0 m down the frictionless ramp shown in the figure , then collides with a spring whose spring constant is 250 N/m.

What is the maximum compression of the spring? ds=2.5m
For what compression of the spring does the box have the maximum speed? ds=??

Homework Equations



Energy is conserved.

Ei = Ef

The Attempt at a Solution



Potential at top of the ramp = Spring potential at ds max

ds=mg/2k(1+sqrt((1+4Lk)/mg)

Which got me the correct answer to the first question
For the second question I tried:

Potential at top of ramp = Kinetic at top of spring = Spring Potential

but I couldn't get a workable solution.

Intuitively I thought the answer would be ds=0, but it wasn't.

Any thoughts?
 
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Consider the net force on the box as it goes through its motion. As long as the net force is down the ramp it will continue to accelerate.
 
Doc Al said:
Consider the net force on the box as it goes through its motion. As long as the net force is down the ramp it will continue to accelerate.

Ah, that did it. I wonder though. When I asked my TA if I could find the ds with Spring Force=Gravitational Force, he said that the final spring compression would be different for an object that is accelerating into the spring versus one that is just in static equilibrium, and that I couldn't use it in this situation. Did his point have any validity?
 
welcome to pf!

hi jzwiep! welcome to pf! :smile:

yes, Spring Force=Gravitational Force only gives you zero acceleration, not zero velocity (except in static equilibrium, when of course they're the same) :wink:
 
jzwiep said:
Ah, that did it. I wonder though. When I asked my TA if I could find the ds with Spring Force=Gravitational Force, he said that the final spring compression would be different for an object that is accelerating into the spring versus one that is just in static equilibrium, and that I couldn't use it in this situation. Did his point have any validity?
Realize that you are solving for two different spring compressions. We are discussing the second one: The compression where speed is maximum. His comments apply to the first question (finding the final or maximum compression), not to the second one.
 
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