Spring Block System: Period & Max Speeds/Accel

AI Thread Summary
The discussion focuses on the oscillation of a 1 kg mass attached to a spring with a force constant of 25 N/m on a frictionless track. The calculated period of the motion is approximately 1.257 seconds, with maximum speed at 0.15 m/s and maximum acceleration at 0.75 m/s². The displacement, velocity, and acceleration as functions of time are given as x = -0.03cos(25t), v = 0.15sin(25t), and a = 0.75cos(25t), respectively. The period of oscillation is independent of the initial compression, as more energy allows for a consistent oscillation regardless of the distance pulled back. The calculations and concepts presented are confirmed to be correct.
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a 1 kg mass attached to a spring with a force constant of 25 oscillates on a horizontal, frictionless track. At time t=0, the mass is released from rest at x=-3cm (the spring is compressed by 3cm). Find (a) the period of its motion. b) the max values of speed and acceleration. c) the displacement, velocity, acceleration as a function of time.

a)
T=2\pi \sqrt{\frac{m}{k}}
T=2\pi \sqrt{\frac{1kg}{25N/m}}
T=1.257s

b)
v_{max}=\omega A=\sqrt{\frac{k}{m}}*A =\sqrt{\frac{25}{1}}*0.03=0.15m/s
a_{max}=\omega ^2 A=\frac{kA}{m} ={\frac{25}{1}}*0.03=0.75m/s^2

c)
x=-0.03cos25t
v=0.15sin25t
a=0.75cos25t

is this all correct?
 
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Looking sexy.
 
so the period does not involve how much was pulled back?
 
Nah.

And this is understandable since if you pull the block back a lot, sure it has a "longer way to go" to the equilibrium position, but it has more energy at its disposal.
 
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