What is the maximum velocity of a block in a spring mechanics problem?

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In a spring mechanics problem involving two blocks of mass 8 kg each, the first block hangs from a spring with a spring constant of 65 N/m, stretching the spring by an additional 1.5 m when the second block is added. When the string holding the second block is cut, the maximum velocity of the first block needs to be calculated. An initial calculation suggests a velocity of 4.3 m/s, but the correct answer is 3.42 m/s. The discrepancy arises from not accounting for the initial stretch of the spring when determining the total displacement. Properly considering the spring's initial stretch is crucial for accurate calculations.
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Homework Statement



A block of mass m1 = 8 kg hangs from the ceiling on an ideal, massless spring with spring constant k = 65 N/m. With the block hanging on the spring, the total length of the spring is L = 3.5 m. When a second block with an identical mass of m2 = 8 kg is tied to the first with a massless string, the spring stretches an additional h0 = 1.5 m.

The string is cut so that mass m2 falls away. What is the maximum velocity of mass m1?

The Attempt at a Solution


\frac{kx^2}{2}=\frac{mv^2}{2}
x=1.5 and solving for v gives 4.3
but the answer is 3.42?
 
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Hi ronaldor9! :smile:
ronaldor9 said:
… With the block hanging on the spring, the total length of the spring is L = 3.5 m. When a second block with an identical mass of m2 = 8 kg is tied to the first with a massless string, the spring stretches an additional h0 = 1.5 m.

x=1.5 and solving for v gives 4.3
but the answer is 3.42?

1.5 isn't x …

you have to (find and) add on the bit of x that's already in the 3.5. :wink:
 
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