Square Loop of Copper Wire Falls out of

AI Thread Summary
To find the terminal velocity of a square loop of copper wire falling out of a magnetic field, one must balance the magnetic force against the gravitational force. Given the magnetic field strength of 1.2T, a side length of 5cm, and a radius of 1mm, the acceleration is zero at terminal velocity. This means that instead of using the equation vf = vi + at, the focus should be on the forces acting on the loop. By equating the magnetic force to the weight of the loop, the terminal velocity can be determined. Understanding this balance is crucial for solving the problem effectively.
ryguy7272
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Homework Statement


I am stuck on a HW problem. A square loop of copper wire falls out of a side 'a' and radius 'r' falls outside of a magnetic field 'B'. How does one find the terminal velocity?
B = 1.2T
a = 5cm
r = 1mm

Please help me set up this problem so I can solve it and figure out what is going on!

Thanks,
Ryan---


Homework Equations


Perhaps...
vf = vi + at


The Attempt at a Solution

 
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ryguy7272 said:
I am stuck on a HW problem. A square loop of copper wire falls out of a side 'a' and radius 'r' falls outside of a magnetic field 'B'. How does one find the terminal velocity?
…
Perhaps...
vf = vi + at

Hi Ryan! Welcome to PF! :smile:

Forget about acceleration!

Terminal velocity means that the acceleration is zero!

So just balance the magnetic force against gravity. :wink:​
 
Ah! Failed to see the obvious.
Thanks!

Regards,
Ryan---
 

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