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Square root of a rational quantity: Algebra

  1. Aug 3, 2011 #1
    Why arnt the two terms eqaul even though the square root of m was solved properly?

    And is this a general rule?
     

    Attached Files:

  2. jcsd
  3. Aug 3, 2011 #2

    Dick

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    I think by 'quadratic surd' they mean that sqrt(m) is irrational where m is rational. Your last expression shows sqrt(m) is a ratio of rationals. Wouldn't that always be rational?
     
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