Standard deviations and probabilities

AI Thread Summary
The discussion revolves around calculating probabilities related to a sample of 0.600 ppm Selenium with a known population standard deviation of 0.005 ppm. For a single determination, the probability of obtaining a value less than 0.590 ppm is calculated to be approximately 2.28%. The second part of the problem, concerning the average of four determinations being less than 0.590 ppm, presents more difficulty, with a referenced probability of 0.0032% for values less than 0.580 ppm. The participants discuss the challenges of using standard deviation tables and the need for a specific equation to solve the second part. Overall, the thread highlights the complexities of statistical probability calculations in this context.
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Homework Statement


Suppose a sample containing 0.600 ppm Selenium is analyzed by a method for which the standard deviation of the population is known to be 0.005 ppm.
1) What is the the probability that a single determination would return a value less than 0.590 ppm?
2) What is the probability that the average for 4 determinations would be less than 0.590 ppm?

Homework Equations


the table at the bottom of http://64.233.167.104/custom?q=cache:bdW_K0aRhzEJ:www.palgrave.com/business/taylor/taylor1/lecturers/lectures/handouts/hChap5.doc+chart+area+beneath+normal+curve+standard+deviations&hl=en&ct=clnk&cd=7&client=pub-8993703457585266" page tells the area under a normal curve for different standard deviations.

The Attempt at a Solution


for 1) we look on the table for 2.0 standard deviations below the mean, and see that the area under the curve is 0.4772. and at infinite standard deviations, the area is necessarily 0.5000.
so to return a value in this range (less than 0.590 ppm) the solution is ( 0.5 - 0.4772 ) * 100%
= 2.28%

for 2) i don't even know where to start. the answer given is 0.0032%. this table doesn't go far enough, but the probability of finding a value less than 0.580 (or 4 standard deviations below) is 0.0032%. I don't know whether that is relevant or not.
the internets and my textbook combined were less than helpful on this as well.
please help!

thanks.
 
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all right! I found the equation to govern this.

let z be the number of standard deviations away from the mean
... u be the mean
... x be the value of a determination
... n be the number of determinations
... s be the standard deviation

z = (| u - x | * (n)^(1/2)) / s
 
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