How Can I Find the Standard Enthalpy of Formation for Any Compound?

AI Thread Summary
To find the standard enthalpy of formation for any compound, reference tables or chemistry textbooks are valuable resources, often containing lists of these values. Pure substances in their elemental state have an enthalpy of formation of zero, which simplifies calculations for compounds formed from these elements. For example, the enthalpy change in reactions can be used to derive the enthalpy of formation for other substances. Online databases, such as the NIST Chemistry WebBook, provide specific enthalpy values for various compounds, including Titanium Nitride (TiN) and Titanium Carbide (TiC). While some values may be readily available, others, like those for Vanadium Carbide (VC) and Vanadium Nitride (VN), may require more extensive research, including historical articles for less common compounds.
Juwad
Messages
33
Reaction score
0
I've google and read, but could anyone tell me how to find out the standard enthalpy of formation for any compound? :confused:


thnx
 
Chemistry news on Phys.org
Juwad said:
for any compound?
For any compound you say? That might be difficult.
Depending on how common the compound is you can often look up the value for its standard enthalpy of formation in a reference table/book somewhere.
Often chemistry textbooks will have a decent list in the back appendixes.

Pure substances in their elemental state have enthalpies of formation equal to zero. For example, both Hydrogen gas (H2) and Oxygen gas (O2) both have an enthalpy of formation of zero, when they react,
2H2 + O2 --> 2H2O + delta H
There is a change in enthalpy (exothermic in this case). Since water is the only thing in the reaction which does not have an enthalpy of formation of zero it makes it easy to find its value. Similar methods can be employed to find the enthalpy of formation values of other substances if you know the change in enthalpy of other reactions.
For example,
C (graphite) + O2 (g) --> CO2 (g) + delta H = -393.5 kJ
C (diamond) + O2 (g) --> CO2 (g) + delta H = -395.4 kJ
Through some clever manipulation,
C (graphite) --> C (Diamond) + delta H = +1.9 kJ
In this case the graphite allotrope of Carbon has a zero enthalpy of formation (it is the most stable form of Carbon), so from this we can infer that the diamond allotrope must have an enthalpy of formation of +1.9 kJ/mol.
 
Juwad said:
I've google and read, but could anyone tell me how to find out the standard enthalpy of formation for any compound? :confused
Here there are many:
http://webbook.nist.gov/chemistry/form-ser.html
Insert the formula and select what you need (example: "condensed phase" if it's a liquid or solid, ecc.)
 
I want to know the standard enthalpy and entropy values for the following:

TiN (Titanium Nitride)
TiC (Titanium Carbide)
VC (Vanadium Carbide)
VN (Vanadium Nitride)
 
I'm unable to open this website due to some blocks applied by higher authority.
If possible, could you copy paste the page.
 
I will not copy the page, due to potential copyright violation ... however the heat of formation listed on that page was 337 kJ/mol (I assume they meant -337 kJ/mol).

That value, along with values for TiC and VN, can be found in the NIST chemistry webbook.

http://webbook.nist.gov

Vanadium carbide is not there, but I found a value of -24.1 kcal/mol (note the different units) in an 1964 article from Journal of Physical Chemistry. Here is the citation:

"The Free Energies of Formation of the Vanadium, Niobium, and Tantalum Carbides"
Wayne L. Worrell, John Chipman
Journal of Physical Chemistry, volume 68, issue 4
pp 860–866.
 
Back
Top