Standing Wave Question: Wavelength of Resultant Wave with Two Opposing Waves

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SUMMARY

The discussion confirms that the wavelength of a resultant standing wave produced by two identical waves traveling in opposite directions is indeed the same as the wavelength of the original waves. This conclusion is supported by the equation for standing waves, ysin(kx)cos(wt), where k is defined as 2π divided by the wavelength. The presence of nodes and antinodes in a standing wave indicates that the original wave properties are preserved, leading to the same wavelength in the resultant wave.

PREREQUISITES
  • Understanding of wave mechanics and properties of waves
  • Familiarity with the concept of standing waves
  • Knowledge of trigonometric identities, specifically sinA + sinB
  • Basic grasp of wave equations, particularly ysin(kx)cos(wt)
NEXT STEPS
  • Study the derivation of standing wave equations in detail
  • Explore the implications of nodes and antinodes in wave behavior
  • Learn about wave interference and its effects on resultant waves
  • Investigate the relationship between wave frequency and wavelength
USEFUL FOR

Students studying physics, particularly those focusing on wave mechanics, as well as educators seeking to clarify concepts related to standing waves and wave properties.

vivekfan
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Homework Statement



If a standing wave is produced by two identical waves traveling in opposite directions, is the wavelength of the resultant wave simply the wavelength of the original wave?


Homework Equations



ysin(kx)cos (wt)

The Attempt at a Solution



I'm pretty sure it produces a wavelength of the original wave because A standing wave requires that the nodes and antinodes remain in the same place, but I want to make sure. Please help!
 
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sinA + sinB == 2sin((A+B)/2)cos((A-B)/2)

so a sin(kx - wt) + a sin(kx + wt) = 2a sin(kx)cos(wt)

k is 2pi/wavelength.

Any help?
 
davieddy said:
sinA + sinB == 2sin((A+B)/2)cos((A-B)/2)

so a sin(kx - wt) + a sin(kx + wt) = 2a sin(kx)cos(wt)

k is 2pi/wavelength.

Any help?

Does that mean that the standing wave has the same wavelength as the original?
 
vivekfan said:
Does that mean that the standing wave has the same wavelength as the original?

I think so.
Try drawing some pictures.
 

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