Godwin Kessy said:
Thanks man! But what i know is that every charge radiates electric fields radialy outwards
Yes, but since there are many charges being modeled (an infinite amount of infinitesimal charges in a uniformly charged object), the electric field often cancels out in all components except for the component perpendicular to the surface (this is certainly true for a conductor).
Imagine an infinitely long, charged wire laying horizontally on the x-axis. A given infinitesimal point charge will have electric field lines drawn spherically outward. So some of its electric field will be drawn in the general direction of the positive x direction. But there is also another infinitesimal charge right next to it, slightly further along the x-axis, who's field lines point in the negative x-axis direction (in-part), canceling out the field line components of the first charge, but only in the x direction. Now if you put an infinite amount of infinitesimal charges on the line all electric field lines cancel except for the field lines pointing radially away from the line.
but what i clearly see on a uniformly charged object is that only a single field among many seems to be shown
Yes, this is due to cancellation of the different components of the different charges. Everything sums up to zero, except for the component pointing radially outward. In a charged conductor, this direction is always perpendicular to the surface, when measured at the surface itself.
also what hapens until a charge on one end of a linear charge distributed conductor can't cause electric flux on the plates of the cylindrical gausian surface drawn!
may u tel me clearly on the interaction and at the same time gauss law says that the net sum of flux is the algebraic sum of the flux due to each charge while the diagram shows that some flux are neglected and i don't really understand what hapens to it?
Gauss' law only works for an
infinitely long charged wire or cylinder, when using a cylindrical Gaussian surface. If the charged wire/cylinder is less than infinitely long, Gauss' law is only an approximation. But it's a pretty good approximation if the place of interest is not near one of the edges, and if the distance to the cylinder/wire is small compared to the length of the cylinder/wire.