Static friction: Will the box move?

AI Thread Summary
A 55.0-kg box on a horizontal surface has a static friction coefficient of 0.300, and a force of 156 N is applied at an 18-degree angle. The initial calculation suggests that the box will not move, as the horizontal component of the applied force (148.36 N) is less than the frictional force (161.865 N). However, the upward component of the applied force needs to be considered, as it reduces the effective weight of the box and thus the normal force. This interaction between the applied force components and gravitational force is crucial in determining whether the box will move. A complete analysis of both force components is necessary to arrive at the correct conclusion.
Shannonvi
Messages
2
Reaction score
0

Homework Statement


A 55.0-kg box rests on a horizontal surface. The coefficient of static friction between the box and the surface is 0.300. A force of 156 N is applied to the box directed at an angle of 18.0 above the horizontal. Does the box move?

Please help??

The Attempt at a Solution


156 (cos18)= .300 (55kg×9.81m/s)
148.36N = 161.865 so no, the box wouldn't move. but my answer is wrong[/B]
 
Physics news on Phys.org
Shannonvi said:

Homework Statement


A 55.0-kg box rests on a horizontal surface. The coefficient of static friction between the box and the surface is 0.300. A force of 156 N is applied to the box directed at an angle of 18.0 above the horizontal. Does the box move?

Please help??

The Attempt at a Solution


156 (cos18)= .300 (55kg×9.81m/s)
148.36N = 161.865 so no, the box wouldn't move. but my answer is wrong[/B]

Does the force of 156N do anything else?
 
PeroK said:
Does the force of 156N do anything else?

I'm not sure what you mean
 
Shannonvi said:
I'm not sure what you mean

It has an upward component.
 
Last edited:
Assuming you're saying the applied force has an upward tilt, break it down into its x and y components. How does this interact with the gravitational force acting on the mass?
 
Moderator's note: Thread title modified to make it more descriptive of the problem being addressed. Thread titles should not be overly generic.
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Static Friction Between a Box and the Floor
Replies
11
Views
3K
Friction problem of a block sandwiched between 2 surfaces
Replies
6
Views
1K
Stopping distance and static friction
Replies
1
Views
4K
Static Friction Required to Keep the System from Moving (Two Boxes)
Replies
16
Views
2K
Question about finding static friction coefficient
Replies
6
Views
2K
Acceleration of object with friction: Homework help
Replies
1
Views
2K
Box Pulled on Rough Horizontal Surface - Frictional Force
Replies
7
Views
9K
Box and a Spring on on an inclined plane
Replies
11
Views
3K
Static and kinetic friction help?
Replies
1
Views
1K
Static friction 2 boxes and force question
Replies
19
Views
12K

Hot Threads

Recent Insights

Back
Top