How to Calculate Forces in a Beam Using the Method of Sections

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The discussion centers on calculating forces in a beam using the method of sections, specifically addressing difficulties in solving for the force in member BC. The user attempted to take moments at point A but is not arriving at the expected answer. A suggestion is made to verify the angle used in calculations, particularly the 30 degrees, and to check the accuracy of the triangles involved. The conversation highlights the importance of correctly identifying angles and geometry in structural analysis. Accurate calculations are crucial for determining forces in beam structures.
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IHi guys with part b of this question I am having trouble. I have cut it it at the specified members and used the top half. Now i take the moment at A to get the force in BC. (CW+)M@A=(6*3)+(6cos(30)*3)=0, But when you solve this it doesn't give you the answer its supposed to be, I am probably blind & missing something. Please check out the attachments i provided some more info on it.

Thankyou in Advance.
 

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Sorry man, its up now
 
Where do you get 30 degrees from? Check your triangles.
 
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