hurrfdurrf
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Homework Statement
[PLAIN]http://img15.imageshack.us/img15/7379/unledtzc.png
(The rods are of length L, there is no friction, massless rods, yadee yadee yada)
At a certain angular speed \omega, the counterweight performs uniform circular motion. Show that \omega and \theta are related as follows:
\omega^2 \cos{\theta} = (1 + \frac{2m'}{m}) \frac{g}{L}
Homework Equations
T_1 = L m \omega^2
\cos{\theta} (T_1 - T_2) = g (m + m')
The Attempt at a Solution
(Working backwards) Combined above to get
T_2 \cos{\theta} = m' g
which makes a lot of sense, but I'm not sure if the procedure was right
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