Stationary Electron accelerated through potential difference

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Discussion Overview

The discussion revolves around calculating the velocity of a stationary electron after it has been accelerated through a potential difference of 500 volts. The focus is on the relationship between potential difference and the resulting velocity, with participants exploring the relevant equations and concepts.

Discussion Character

  • Technical explanation, Mathematical reasoning, Homework-related

Main Points Raised

  • One participant expresses uncertainty about how to calculate the velocity of an electron accelerated by a potential difference, indicating a lack of familiarity with the relevant equations.
  • Another participant prompts for clarification on the energy involved in the acceleration process.
  • A third participant references an external thread for additional context or information, suggesting that the question may have been addressed previously.
  • A participant proposes an equation relating charge, potential difference, mass, and velocity, suggesting a conversion to express velocity in terms of these variables.
  • Another participant confirms the proposed equation, indicating that the relationship can be expressed as v^2 = 2eV/m.

Areas of Agreement / Disagreement

There is no explicit consensus on the method of calculation, but participants are engaging with the problem and refining their understanding of the relevant equations.

Contextual Notes

The discussion does not clarify the assumptions regarding the mass of the electron or the context of the potential difference, which may affect the calculations.

Who May Find This Useful

Students or individuals interested in the physics of charged particles, particularly in the context of electric fields and potential differences.

dr.mt
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I have this question that asks what the velocity of the stationary electron is after being accelerated by potential difference. The potential difference is 500v, but the specific potential difference doesn't concern me. I'm uncertain of how i get the velocity, because i don't know an equation for velocity affected by potential difference. i feel as though this is incredibly simple and I'm missing something.
 
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Do you know what the energy might be?
 
Oh alright, yep simple mistake. it'd be qV=(mv^2)/2 converted to veloctiy= (2qV/m)^(1/2) right?
 
Thank you ZapperZ. v^2= 2eV/m
 

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