Statistic student return and forgot it all

  • Thread starter Thread starter yeungmei
  • Start date Start date
  • Tags Tags
    Statistic Student
AI Thread Summary
The discussion centers on calculating the number of students expected to be unable to complete a 90-minute exam, given a normal distribution with a mean of 80 minutes and a standard deviation of 10 minutes. The key steps involve finding the z-score for 90 minutes, which indicates how many standard deviations this time is from the mean. Participants suggest using the normal distribution to determine the percentage of students who will exceed this time limit. The final calculation requires multiplying this percentage by the total number of students in the class. Understanding these statistical concepts is essential for accurately predicting exam completion rates.
yeungmei
Messages
7
Reaction score
0
I studied stat couple years ago, and going back again...here goes...

THe time needed to complete a final examination in a particular college course is normally distributed with a mean of 80 minutes and a standard deviation of 10 minutes.

Assume that the class has students and that the examination period is 90 mintues in length. How many students do you expect will be unable to complete the exam in the allotted time?

so, i know mean is 80 and SD is 10, and the z is 90...am i find the "n" in the case?? How do i find it? by using what formula??o:)
 
Physics news on Phys.org
I think you have to find out what percent of the normal distribution is beyond one standard deviation. Then, multiply that percentage by the amount of students taking the test and you should have your answer.
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
Back
Top