Stats - find the distribution function of an infinite sample space.

AI Thread Summary
The discussion focuses on determining the distribution function for rolling a die until a six appears for the first time, with the probability of this event occurring on the nth roll expressed as (5/6)^(n-1) * (1/6). The infinite sample space is defined as Ω = {6, N6, NN6, NNN6, ...}. Participants emphasize the importance of correctly representing the formula and clarifying notation, particularly regarding the summation notation and the concept of infinity. It is confirmed that the series converges to 1, validating the distribution function. Overall, the key points revolve around the correct formulation and understanding of the infinite sample space and its properties.
dtsar
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Homework Statement



A die is rolled until the first time that a six turns up. We shall see that the
probability that this occurs on the nth roll is (5/6)n−1 · (1/6). Using this fact,
describe the appropriate infinite sample space and distribution function for
the experiment of rolling a die until a six turns up for the first time. Verify
that for your distribution function the Ʃ(ω)=1, as ω→∞

Homework Equations



Relevant equations are in the question.

The Attempt at a Solution


Ω = { 6, N6, NN6, NNN6, ... , N...N6 }
Also, I know that the equation is exponential decay, but I just don't know how to get the formula...
I also know that it adds up, because (1/6)+(5/6)(1/6) + (5/6)^2(1/6) .. etc eventually equal to 1 as N→∞
 
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dtsar said:

Homework Statement



A die is rolled until the first time that a six turns up. We shall see that the
probability that this occurs on the nth roll is (5/6)n−1 · (1/6). Using this fact,
describe the appropriate infinite sample space and distribution function for
the experiment of rolling a die until a six turns up for the first time. Verify
that for your distribution function the Ʃ(ω)=1, as ω→∞

Homework Equations



Relevant equations are in the question.


The Attempt at a Solution


Ω = { 6, N6, NN6, NNN6, ... , N...N6 }
Also, I know that the equation is exponential decay, but I just don't know how to get the formula...
I also know that it adds up, because (1/6)+(5/6)(1/6) + (5/6)^2(1/6) .. etc eventually equal to 1 as N→∞

(i) What you wrote was (5/6)n-1 - 1.(1/6), which means (5n/6) - (1/6). You should have written either (5/6)^(n-1) - (1/6) or used the "S U P" button to get (5/6)n-1 - (1/6).
(ii) Saying Ʃ(ω)=1, as ω→∞ makes no sense: the ω need not be numbers, so they can't "go to infinity". Just saying Ʃ(ω)=1 is enough.
(iii) You write Ω as though it has an "end", but it doesn't just write Ω = {6, N6, NN6, NNN6, ... }. Also, if you use N here you should not later say "as N → ∞". Use a different symbol.

Aside from these writing issues, I don't see your problem; you seem to have answered the questions you were asked. For example, when you say "I just don't know how to get the formula...", that is not relevant: you are *given* the formula, and are asked to use it. You have done that correctly.

RGV
 
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