Stats Help Using Standard deviation and a population

AI Thread Summary
Joan finished the Bolder Boulder 10K race 1.75 standard deviations faster than the average for her age group, which includes 405 women. To determine how many women ran faster than her, it's essential to understand the standard normal distribution. Approximately 95.99% of the population is slower than Joan, meaning about 16 women ran faster than her. The calculations involve using the z-score and multiplying the corresponding probability by the total number of participants. The final conclusion is that 16 runners finished ahead of Joan.
Kingyou123
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Homework Statement


Joan’s finishing time for the Bolder Boulder 10K race was 1.75 standard deviations faster than the women’s average for her age group. There were 405 women who ran in her age group. Assuming a normal distribution, how many women ran faster than Joan.

Homework Equations



The Attempt at a Solution


I know Joan ran in between the 1st and 2nd standard deviation I'm just confused on how to split up the population correctly. Would the first deviation be 68% of the population?
 
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Kingyou123 said:

Homework Statement


Joan’s finishing time for the Bolder Boulder 10K race was 1.75 standard deviations faster than the women’s average for her age group. There were 405 women who ran in her age group. Assuming a normal distribution, how many women ran faster than Joan.

Homework Equations



The Attempt at a Solution


I know Joan ran in between the 1st and 2nd standard deviation I'm just confused on how to split up the population correctly. Would the first deviation be 68% of the population?
No. About 34% of the population will have scores between z = 0 and z = 1. Between z = -1 and z = 1 (i.e., within 1 st. deviation of the mean), there is about 68% of the population. You need to figure out how many are included between z = 0 and z = 1.75 -- a standard normal distribution table will be helpful. Don't forget to add the half of the race participants whose z scores are less than or equal to 0.
 
Mark44 said:
No. About 34% of the population will have scores between z = 0 and z = 1. Between z = -1 and z = 1 (i.e., within 1 st. deviation of the mean), there is about 68% of the population. You need to figure out how many are included between z = 0 and z = 1.75 -- a standard normal distribution table will be helpful. Don't forget to add the half of the race participants whose z scores are less than or equal to 0.
So "z" would equal .4599, I'm assuming you would multiply it by 405 to get the number of runners who are faster than her. So the answer would be 186 runners?
 
Kingyou123 said:
So "z" would equal .4599, I'm assuming you would multiply it by 405 to get the number of runners who are faster than her. So the answer would be 186 runners?
No z = 1.75. I think what you found was P(0 < z < 1.75) = .4599.

Do you understand what z is? If not it's the variable for a standard normal distribution; one with mean 0 and standard deviation 1. The total area under the graph of the distribution is 1. This area (or probabillity) includes ##P(-\infty < z < 0)##, which is .5 and P(0 < z < 1.75). What proportion of the runners are faster than she is? I don't think your answer of 186 is correct.
 
Mark44 said:
No z = 1.75. I think what you found was P(0 < z < 1.75) = .4599.

Do you understand what z is? If not it's the variable for a standard normal distribution; one with mean 0 and standard deviation 1. The total area under the graph of the distribution is 1. This area (or probabillity) includes ##P(-\infty < z < 0)##, which is .5 and P(0 < z < 1.75). What proportion of the runners are faster than she is? I don't think your answer of 186 is correct.
My professor talked about standard deviation for a short time, maybe 8 minutes. So I understand that P(-infy<z<) and P(0 < z < 1.75) gives me the proportion of runners that are slower than her, however I'm confused on what the next step would be from there. Would it be as simple as multiplying the sum of both proportions by 405 to get a number than subtracting that number from 405 to get the number of runners that are faster than she is?
Edit:
.9599*405=388.75

405-388.75= 16.25 or 16 runners are faster than Joan
 
Kingyou123 said:
My professor talked about standard deviation for a short time, maybe 8 minutes. So I understand that P(-infy<z<) and P(0 < z < 1.75) gives me the proportion of runners that are slower than her, however I'm confused on what the next step would be from there. Would it be as simple as multiplying the sum of both proportions by 405 to get a number than subtracting that number from 405 to get the number of runners that are faster than she is?
Edit:
.9599*405=388.75

405-388.75= 16.25 or 16 runners are faster than Joan
Looks good
 
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