A Stellar photosphere temperatures

AI Thread Summary
Star surface temperature influences the photosphere, where radiation escapes due to reduced gas ionization and absorption. The discussion highlights that if all star photospheres had the same temperature, the Hertzsprung-Russell diagram would appear as a single point, which is incorrect as stars exhibit a range of temperatures. The initial mass of a star determines its temperature differences, with various internal mechanisms maintaining equilibrium between fusion energy and surface emission. Transparency of gas, influenced by both temperature and density, allows for different photosphere temperatures among stars. The conversation emphasizes the complexity of stellar structures and the importance of not oversimplifying their behavior in astrophysical models.
astrotizio
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Hi all,
Star surface temperature determines the occurrence of photosphere, where radiation can escape from star interior due to diminishing gas ionization and radiation absorption.
If it was true the star photospheres should have the same temperature and Herzsprung-Russell diagram should be only a point.
Actually initial mass should determine the difference, but what is the machanism?
What is wrong in this reasoning.
I refer to cosmic background radiation map that is defined our universe photosphere with an emission temperature of about some thousand degree Kelvin, temperature at which plasma ionization ceases.
Thanks of your time

Tiziano Colombo
 
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astrotizio said:
If it was true the star photospheres should have the same temperature
That's obviously not true; we see stars whose equivalent surface temperature ranges from rather cool (red dwarf and red giants) to extremely hot (blue stars).

Actually initial mass should determine the difference, but what is the mechanism?
Stars on the main sequence are in a state of equilibrium, more or less. The energy produced by fusion at the center of the star is typically balanced by the energy emitted from the surface of the star. Internally, stars have a number of negative feedback mechanisms that keep the temperature, pressure, and fusion rates in balance. How this relates to energy emitted from the surface of the star is a bit complex due to the various mechanisms by which energy is transferred outwards from a star's core. Red dwarfs are fully convective throughout. Solar mass stars (~0.5 solar masses to ~1.5 solar masses for high metallicity stars) have a non-convective core surrounded by a convective zone. Larger stars, where the CNO cycle dominates over the *pp* chain, have a convective core surrounded by a non-convective outer layer.

What is wrong in this reasoning?
I refer to cosmic background radiation map that is defined our universe photosphere with an emission temperature of about some thousand degree Kelvin, temperature at which plasma ionization ceases.
What is wrong with your reasoning is that you are extrapolating, and you are doing so across many orders of magnitude. The answer is "don't do that then." In other words, don't extrapolate.
 
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Thanks for your answer
 
The transparency of gas depends on its temperature, but not only temperature: it also depends on density (and other factors). Considering just temperature and density, photosphere might happen in low density, high temperature gas, or in high density, low temperature gas. This is what allows stars to have different temperatures.
 
This is a convincing answer, thanks
 
astrotizio said:
Hi all,
Star surface temperature determines the occurrence of photosphere, where radiation can escape from star interior due to diminishing gas ionization and radiation absorption.
If it was true the star photospheres should have the same temperature and Herzsprung-Russell diagram should be only a point.
Also this would not follow. If all star photospheres had the same temperature, they could still have different luminosities and radii, and form a line rather than a point on Herzsprung-Russell diagram.
 
I agree, a point in the H-R diagram was a banal error.
With the same temperature but different radii you obtain different luminosities in the vertical axis, following
L = 4*pi*R^2*T^4
 
Sorry in the previous expression i forgot a constant
 
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