Stochastic difference equation?

Click For Summary
SUMMARY

The discussion centers on solving a stochastic difference equation involving variables P, U, and V, with constants a, b, c, and d, measured over discrete time periods. The user successfully derived up to equation 2 but struggles with extracting P from the left-hand side of the equation. The key insight is recognizing that L acts as a shift operator, where Lp_t equals p_{t-1}, indicating that this operator is not a multiplication but rather a transformation of the variable P over time.

PREREQUISITES
  • Understanding of stochastic difference equations
  • Familiarity with shift operators in mathematical notation
  • Basic algebraic manipulation skills
  • Knowledge of discrete time modeling
NEXT STEPS
  • Research the properties and applications of stochastic difference equations
  • Learn about shift operators and their role in time series analysis
  • Study examples of extracting variables in difference equations
  • Explore the relationship between stochastic processes and discrete time models
USEFUL FOR

Students and researchers in mathematics, particularly those focusing on difference equations, stochastic processes, and discrete time modeling techniques.

Link
Messages
132
Reaction score
1

Homework Statement




This is a question about one single step of a solution of a long equation.

http://www.geocities.com/link_herooftime/math.jpg

where P, U and V are variables. a, b, c, d are constants and t is the time, which are measured in discrete periods.

The question is how to go from equation 1 to equation 3, and how the L appears.

Attempted solution


I have solved it until equation 2, and I see that the solution requires the extraction of P out of the bracket on the left hand side. Problem becomes how to do it, since the P minus one period doesn't equal P of current period. Nevertheless the key somehow does this. Does this require some other method than simple algebra?

The key mentions it is a "stochastic difference equation".
 
Physics news on Phys.org
Just looking at it, L appears to be a shift operator, that is [itex]Lp_t=p_{t-1}[/itex]. Note that [itex]Lp_t[/itex] is not multiplication, but rather the L operator is applied to [itex]t_p[/itex]. Another example of this kind of notation involves the differential operator [itex]D_x[/itex], in particular [itex]D_xf(x)[/itex] is the derivative of f(x) w.r.t. x.
 

Similar threads

Replies
6
Views
1K
  • · Replies 29 ·
Replies
29
Views
2K
Replies
7
Views
2K
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K