Straight-Line Graph: x/t2 and t or x/t Pairs for Plotting

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The discussion focuses on determining which pairs of quantities yield a straight-line graph for a stone sliding across an icy surface with uniform retardation. The initial analysis suggests that the pair x/t2 and t produces a flat line, while x/t and t also represents a straight-line graph due to constant deceleration. However, there is confusion regarding the full equation for position, as participants debate the inclusion of initial velocity in the formula. The correct equation for position is clarified as x = v_0t + 0.5at^2, indicating that initial velocity must be considered. Ultimately, the conversation highlights the importance of accurately applying kinematic equations in analyzing motion.
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A stone slides across an icy surface and travels a distance of x in time t while suffering uniform retardation. Which of the following pairs of quantities, plotted to represent the motion of the stone, would give a straight-line graph?

A. x and t
B. x and t2
C. x/t and t2
D. x/t and t
E. x/t2 and t

This is my approach to the problem:

The initial velocity, u = at.

Hence, the distance traveled by the stone, x = 0.5at2

x/t2 = (0.5at2)/t2

= 0.5a

Since a is a constant, then a flat line would be represented in a graph of axes x/t2 and t.

Also, in D., x/t = v, which decreases at a constant rate because of the constant deceleration, so this is another straight-line graph.

Obviously, there must be something wrong with my reasoning because there can only be one, and not two answers for each multiple choice question.
 
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recon said:
The initial velocity, u = at.

Hence, the distance traveled by the stone, x = 0.5at2

Are you sure that's the full equation for position as a function of time? What about the initial velocity?
 
x = at(t) + 0.5 at2
= 1.5 at2 ?

This does not seem right.
 
Have you ever seen the formula:

x=v_0t+\frac{1}{2}at^2
 
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