- #1

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1. The cube is dropped from height h

2. The cube is relatively small, thus we can neglect air resistance

[tex]\frac{\Delta p}{\Delta t} = F[/tex]

[tex]F = \frac{m \Delta v}{\Delta t}[/tex]

[tex]\Delta v = -\sqrt{2gh}[/tex]

[tex]F = \frac{-m\sqrt{2gh}}{\Delta t}[/tex]

Now, I do not have an idea how to find the distance of the collision. It seems that the only way would be to measure the deformation of concrete under the cube (I assume the cube does not bounce upwards).

Is there a way to estimate how long the collision will last?