Struggling to Find X(t) Using Inverse Laplace Transform

schapman22
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Homework Statement



Having found the laplace transform of a differential equation. I must now find X(t). All of my work is attached. The problem I am having is fitting my function of s to my table of transforms. I tried using partial fractions but it took me in a loop.

The Attempt at a Solution



I attached everything.
 

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I know the answer is et which means somehow 1/(s-1)2 becomes 1/(s-1). But I don't understand how to get rid of the other (s-1) in the denominator.
 
Hey I still can't figure this one out. If anyone has any advice it would be very much appreciated. Thank you.
 
I have trouble reading your images, but if you are trying to inverse ##\frac 1 {(s-1)^2}## you can use one of the shifting theorems$$
\mathcal L^{-1}f(s-a) = e^{at}\mathcal L^{-1}f(s)$$Do you see how to use that? Your answer isn't just ##e^t##.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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