Stuck on a 1500hp Pump Problem: Solve for Velocity & Efficiency

AI Thread Summary
To solve the 1500hp pump problem, the focus should be on the relationship between kinetic energy (KE) and gravitational potential energy (PE) rather than the pipe size. The water's velocity can be determined using the formula for kinetic energy, which relates to how high the water is projected. The overall efficiency of the pump, set at 60%, will help calculate the flow rate in liters per minute once the velocity is established. Understanding the conversion between KE and PE is crucial for finding the speed at which the water exits the pump. Clarifying these energy concepts will aid in resolving the problem effectively.
crslax9
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I have been working on this problem for 2 days and can't seem to figure it out..

A 1500hp pump throws a jet of water 125 m into the air. (a) With what speed does the water leave the mouth of the fountain. (b) If the overall efficiency is 60%, how many liters of water per minute are thrown into the air?

Thank you for the help as I am pulling my hair out.

I think where I am getting lost is that I need to find the velocity without knowing the size of the pipe. Am I on the right track? Should I be using a motion equation to first get the velocity?

I am just not sure why I am getting so stuck on this problem.
 
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crslax9 said:
I think where I am getting lost is that I need to find the velocity without knowing the size of the pipe. Am I on the right track?

No, you're barking up the wrong tree. Think energy, as in:

How much kinetic energy must, say, 1kg of water have had in order to make it 125 feet in the air?
 
Tom Mattson said:
No, you're barking up the wrong tree. Think energy, as in:

How much kinetic energy must, say, 1kg of water have had in order to make it 125 feet in the air?

so if kinetic energy is (1/2)mv^2 all over v what numbers go where? Maybe this is where I am getting lost? If the v on the top of the equation is velocity and the v on the bottom is volume correct?
 
crslax9 said:
If the v on the top of the equation is velocity and the v on the bottom is volume correct?

I have no idea of what you are saying here.

You're interested in the speed with which the water leaves the pump, right? Well then wouldn't it make sense to consider the KE at the location of the pump, and the PE at the top of the arc?
 
Tom Mattson said:
I have no idea of what you are saying here.

You're interested in the speed with which the water leaves the pump, right? Well then wouldn't it make sense to consider the KE at the location of the pump, and the PE at the top of the arc?

Yes it does make sense but like I said I am lost on what formulas to use and how to use them. it has been a long time since I last had physics.

If you can give me an idea of what to use to begin this equation I think I may be able to go from there.

Thank you for your help so far
 
crslax9 said:
If you can give me an idea of what to use to begin this equation I think I may be able to go from there.

You need the equations for kinetic energy and for gravitational potential energy.
 
okay I know both of those equations, but why do I need to know gpe if I only need the speed of the water at the pumps mouth?
 
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