Stuck on a thermodynamics question (1st law)

AI Thread Summary
The discussion revolves around a thermodynamics problem involving the heating of a bear during hibernation using arachidonic acid. The user calculated the heat required to warm the bear, determining it to be -41800 kJ, and found the enthalpy change for the combustion of arachidonic acid to be -43.3 kJ/mol. They seek guidance on how to use these values to find the mass of arachidonic acid needed. A hint is provided suggesting that the user should calculate the number of moles required to produce 41800 kJ and then convert that to mass using the molecular weight of arachidonic acid. The discussion emphasizes the application of thermodynamic principles to solve the problem.
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Homework Statement



1.Hibernation is a state of regulated hypothermia, lasting several days or weeks, that allows animals to conserve energy during the winter, During hibernation animals slow their metabolism to a very low level, with body temperature and breathing rates lowered, gradually using up the body fat reserves stored during warmer months. The heat required to sustain animals that hibernate comes from the combustion of fatty acids, one ofwhich is arachidonic acid, a 20 –carbon omega-6 fatty acid: C20H32O2 (s)
Calculate the mass of arachidonic acid needed to warm a 500.0 kg bear from 5 to 250C
Assume that the average heat capacity of bear flesh is 4.18 J/g-deg
∆H0f (C20H32O2 (s) ) = -636 kJ/mol ; ∆H0f (CO2 (g) )= -393.5 kJ/mol ; ∆H0f(H2O (l) ) = -285.8 kJ/mol

Homework Equations



Q=mc∆T

Heats of formation

The Attempt at a Solution



well the i found the amount of heat lost by the arachidonic acid needed to warm the bear which was -41800 KJ

and i found the ∆H for the combustion of arachidonic acid using hess' law, which i got -43.3 KJ/mol

but thing is i have to idea what to do with these two pieces of information, help anyone?
 
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Hint: If one mole of arachidonic acid produces 43.5 kJ energy, how many moles are required to produce 41800 kJ? Once you have this number, multiply it by the molecular weight of arachidonic acid to get the mass needed.

I have not checked your calculations. I am assuming they are correct.
 
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