Stuck on this simple physics problem.

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To solve the problem of two buses moving at different speeds, establish that the first bus travels at 42 km/h and the second at 54 km/h, with an initial distance of 18 km between them. The time taken for both buses to cover their respective distances can be expressed using the formula t = d/v. Setting up the equation x/42 = (x + 18)/54 allows for solving for x, the distance traveled by the first bus when the second catches up. By rearranging and solving this equation, the time it takes for the second bus to catch up can be determined. This approach eliminates the need for a table and directly utilizes the relationship between distance, speed, and time.
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Homework Statement



Two buses are moving at constant speeds, in the same direction, the first at 42 km/h and the second at 54 km/h. They are 18 km apart. How long will it take the second bus to catch up to the first? (4 marks)


Homework Equations



average velocity = d/t

The Attempt at a Solution



Ok well first I tried to make a table of the graph but then I remembered that they were 18 km apart so then I had to rethink and I'm still really stuck on this.
 
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When they catch up, the first bus moves through x km and second bus moves through x + 18 km, and they must have taken the same time to cover that distance.

Can you proceed now?
 
What would be a formula that could solve for this?

Or do I have to use a table?
 
Velocity = x/t. So t = x/v.

Since t is the same

x/v1 = (x+18)/v2

v1 and v2 are given. Solve for x.
 
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