Studying for math test - A few things I dont understand

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The discussion focuses on solving a math problem involving finding coefficients a and b in a cubic polynomial given two factors. The user initially attempts to derive simultaneous equations from the roots but encounters inconsistencies in their calculations. Other participants suggest alternative approaches to confirm the values of a and b, pointing out errors in the user's equations. Additionally, they discuss methods for finding the remaining factor of the cubic polynomial, emphasizing that both polynomial division and factorization can be effective. Clarifications on the correct equations and methods are provided to aid in understanding the problem.
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I have a math test coming up and I have last years test in front of me for a study guide. I can do most of the questions on this test and I know the theory behind everything on it but here's a couple of questions that I can't seem to get right.

Q1) If (x + 1) and (x - 2) are factors of x3 + 2x2 + ax + b find the values of a,b E(that greek symbol that looks like a rounded E) R, and find remaining factor.
I assumed that to find a and b I would have to plug each root -1 and 2 into the equation so I have 2 simultaneous equations but it didn't work out for some reason.

Heres what I did
(-1)3 + 2(-1)2 + a(-1) + b = 0 =>a - b = 1
did the same with the other root and got
2a + b = 16

by elimination I got A=17/3 and B=5 but these don't seem to plug into the equation. Am I going about this question the right way?

Also it asks me to find the last factor. I know I can do that by dividing the factors I have into the equation but is that the quickest method to obtaining the final factor when you already have 2?
 
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You can do it 2 ways,

1) you know that (x+1) and (x-2) are factors of that cubic, therefore you know the last root is real too (conjugate pairs and such) so it will be of the form (x - z)

So x^3 + 2x^2 + ax + b = (x+1)(x-2)(x-z), figure it out :)

2) since (x+1) and (x-2) are roots of that equation, then if we define

f(x) = x^3 + 2x^2 + ax + b, then f(-1) = f(2) = 0

Therefore -1 + 2 - a + b = 0 i.e. 1 - a + b = 0 which gives us a - b = 1 as you said

and

8 + 8 + 2a + b = 0 i.e. 16 + 2a + b = 0 which is the same as 2a + b = -16 which is not what you have. Maybe you want to try again?
 
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