- #1
suspenc3
- 402
- 0
Hi, I am having a little bit of trouble with the following:
[tex]\int sintsec^2(cost)dt[/tex]
heres what I have so far
[tex]u=cost[/tex]
[tex]du=-sintdt[/tex]
[tex]-\int sec^2(u)du[/tex]
[tex]-2tan(u) + C[/tex]
is this right?
[tex]\int sintsec^2(cost)dt[/tex]
heres what I have so far
[tex]u=cost[/tex]
[tex]du=-sintdt[/tex]
[tex]-\int sec^2(u)du[/tex]
[tex]-2tan(u) + C[/tex]
is this right?
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